Submission #1564394


Source Code Expand

#include<iostream>
#include<cmath>
#include<iomanip>
#include<cstdio>
#include<algorithm>
#include<set>
#include<map>
#include<queue>
#include<cassert>
#define PB push_back
#define MP make_pair
#define sz(v) (in((v).size()))
#define forn(i,n) for(in i=0;i<(n);++i)
#define forv(i,v) forn(i,sz(v))
#define fors(i,s) for(auto i=(s).begin();i!=(s).end();++i)
#define all(v) (v).begin(),(v).end()
using namespace std;
typedef long long in;
typedef vector<in> VI;
typedef vector<VI> VVI;
in p2(in a){
  return 1LL<<a;
}
struct unifnd{
  VI ht,pr;
  in fnd(in a){
    in ta=a;
    while(a!=pr[a])a=pr[a];
    in tt=ta;
    while(ta!=a){
      tt=pr[ta];
      pr[ta]=a;
      ta=tt;
    }
    return a;
  }
  void uni(in a, in b){
    a=fnd(a);
    b=fnd(b);
    if(a==b)return;
    if(ht[b]<ht[a])swap(a,b);
    pr[a]=b;
    ht[b]+=(ht[a]==ht[b]);
  }
  void ini(in n){
    ht.resize(n);
    pr.resize(n);
    forn(i,n){
      ht[i]=0;
      pr[i]=i;
    }
  }
};
unifnd tfd;
vector<double> x,y,a;
vector<double> bspan;
vector<pair<double,pair<in,in> > > egs;
double sq(double d){
  return d*d;
}
double dist(in i, in j){
  return sqrt(sq(x[i]-x[j])+sq(y[i]-y[j]));
}
vector<double> btot;
int main(){
  ios::sync_with_stdio(0);
  cin.tie(0);
  in n;
  cin>>n;
  x=y=a=vector<double>(n);
  forn(i,n){
    cin>>x[i]>>y[i]>>a[i];
  }
  forn(i,n){
    forn(j,i){
      egs.PB(MP(dist(i,j),MP(i,j)));
    }
  }
  sort(all(egs));
  bspan.resize(p2(n));
  bspan[0]=2e9;
  in ta,tb;
  forn(msk,p2(n)){
    if(!msk)
      continue;
    double tsm=0;
    in tcnt=0;
    tfd.ini(n);
    forn(i,n){
      if(msk&p2(i)){
	tsm+=a[i];
	++tcnt;
      }
    }
    for(auto& eg:egs){
      ta=eg.second.first;
      tb=eg.second.second;
      if((msk&p2(ta))&&(msk&p2(tb))){
	if(tfd.fnd(ta)!=tfd.fnd(tb)){
	  tfd.uni(ta,tb);
	  tsm-=eg.first;
	}
      }
    }
    bspan[msk]=max(0.0,tsm/tcnt);
  }
  btot.resize(p2(n));
  btot[0]=2e9;
  forn(msk,p2(n)){
    if(!msk)
      continue;
    for(in lmsk=msk;lmsk>0;lmsk=(lmsk-1)&msk){
      btot[msk]=max(btot[msk],min(btot[msk^lmsk],bspan[lmsk]));
    }
  }
  cout<<setprecision(15);
  cout<<btot[p2(n)-1]<<endl;
  return 0;
}

Submission Info

Submission Time
Task E - Water Distribution
User w4yneb0t
Language C++14 (GCC 5.4.1)
Score 1000
Code Size 2269 Byte
Status AC
Exec Time 42 ms
Memory 768 KB

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 1000 / 1000
Status
AC × 2
AC × 46
Set Name Test Cases
Sample example0.txt, example1.txt
All 000.txt, 001.txt, 002.txt, 003.txt, 004.txt, 005.txt, 006.txt, 007.txt, 008.txt, 009.txt, 010.txt, 011.txt, 012.txt, 013.txt, 014.txt, 015.txt, 016.txt, 017.txt, 018.txt, 019.txt, 020.txt, 021.txt, 022.txt, 023.txt, 024.txt, 025.txt, 026.txt, 027.txt, 028.txt, 029.txt, 030.txt, 031.txt, 032.txt, 033.txt, 034.txt, 035.txt, 036.txt, 037.txt, 038.txt, 039.txt, 040.txt, 041.txt, 042.txt, 043.txt, example0.txt, example1.txt
Case Name Status Exec Time Memory
000.txt AC 40 ms 768 KB
001.txt AC 42 ms 768 KB
002.txt AC 42 ms 768 KB
003.txt AC 41 ms 768 KB
004.txt AC 42 ms 768 KB
005.txt AC 39 ms 768 KB
006.txt AC 41 ms 768 KB
007.txt AC 41 ms 768 KB
008.txt AC 40 ms 768 KB
009.txt AC 41 ms 768 KB
010.txt AC 41 ms 768 KB
011.txt AC 40 ms 768 KB
012.txt AC 42 ms 768 KB
013.txt AC 42 ms 768 KB
014.txt AC 41 ms 768 KB
015.txt AC 41 ms 768 KB
016.txt AC 42 ms 768 KB
017.txt AC 41 ms 768 KB
018.txt AC 41 ms 768 KB
019.txt AC 42 ms 768 KB
020.txt AC 41 ms 768 KB
021.txt AC 41 ms 768 KB
022.txt AC 41 ms 768 KB
023.txt AC 42 ms 768 KB
024.txt AC 41 ms 768 KB
025.txt AC 41 ms 768 KB
026.txt AC 41 ms 768 KB
027.txt AC 41 ms 768 KB
028.txt AC 41 ms 768 KB
029.txt AC 41 ms 768 KB
030.txt AC 41 ms 768 KB
031.txt AC 41 ms 768 KB
032.txt AC 41 ms 768 KB
033.txt AC 41 ms 768 KB
034.txt AC 39 ms 768 KB
035.txt AC 41 ms 768 KB
036.txt AC 41 ms 768 KB
037.txt AC 41 ms 768 KB
038.txt AC 41 ms 768 KB
039.txt AC 41 ms 768 KB
040.txt AC 1 ms 256 KB
041.txt AC 1 ms 256 KB
042.txt AC 1 ms 256 KB
043.txt AC 1 ms 256 KB
example0.txt AC 1 ms 256 KB
example1.txt AC 41 ms 768 KB